Optimal. Leaf size=200 \[ \frac{105 b^{3/2} e^3 \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{8 (b d-a e)^{11/2}}-\frac{105 b e^3}{8 \sqrt{d+e x} (b d-a e)^5}-\frac{35 e^3}{8 (d+e x)^{3/2} (b d-a e)^4}-\frac{21 e^2}{8 (a+b x) (d+e x)^{3/2} (b d-a e)^3}+\frac{3 e}{4 (a+b x)^2 (d+e x)^{3/2} (b d-a e)^2}-\frac{1}{3 (a+b x)^3 (d+e x)^{3/2} (b d-a e)} \]
[Out]
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Rubi [A] time = 0.417831, antiderivative size = 200, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.179 \[ \frac{105 b^{3/2} e^3 \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{8 (b d-a e)^{11/2}}-\frac{105 b e^3}{8 \sqrt{d+e x} (b d-a e)^5}-\frac{35 e^3}{8 (d+e x)^{3/2} (b d-a e)^4}-\frac{21 e^2}{8 (a+b x) (d+e x)^{3/2} (b d-a e)^3}+\frac{3 e}{4 (a+b x)^2 (d+e x)^{3/2} (b d-a e)^2}-\frac{1}{3 (a+b x)^3 (d+e x)^{3/2} (b d-a e)} \]
Antiderivative was successfully verified.
[In] Int[1/((d + e*x)^(5/2)*(a^2 + 2*a*b*x + b^2*x^2)^2),x]
[Out]
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Rubi in Sympy [A] time = 101.458, size = 192, normalized size = 0.96 \[ \frac{105 b^{\frac{3}{2}} e^{3} \operatorname{atan}{\left (\frac{\sqrt{b} \sqrt{d + e x}}{\sqrt{a e - b d}} \right )}}{8 \left (a e - b d\right )^{\frac{11}{2}}} + \frac{105 b^{2} e^{2} \sqrt{d + e x}}{8 \left (a + b x\right ) \left (a e - b d\right )^{5}} + \frac{35 b^{2} e \sqrt{d + e x}}{4 \left (a + b x\right )^{2} \left (a e - b d\right )^{4}} + \frac{7 b^{2} \sqrt{d + e x}}{\left (a + b x\right )^{3} \left (a e - b d\right )^{3}} + \frac{6 b}{\left (a + b x\right )^{3} \sqrt{d + e x} \left (a e - b d\right )^{2}} - \frac{2}{3 \left (a + b x\right )^{3} \left (d + e x\right )^{\frac{3}{2}} \left (a e - b d\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/(e*x+d)**(5/2)/(b**2*x**2+2*a*b*x+a**2)**2,x)
[Out]
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Mathematica [A] time = 0.824879, size = 167, normalized size = 0.84 \[ \frac{1}{24} \left (\frac{315 b^{3/2} e^3 \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{11/2}}+\frac{\sqrt{d+e x} \left (\frac{34 b^2 e (b d-a e)}{(a+b x)^2}-\frac{8 b^2 (b d-a e)^2}{(a+b x)^3}-\frac{123 b^2 e^2}{a+b x}+\frac{16 e^3 (a e-b d)}{(d+e x)^2}-\frac{192 b e^3}{d+e x}\right )}{(b d-a e)^5}\right ) \]
Antiderivative was successfully verified.
[In] Integrate[1/((d + e*x)^(5/2)*(a^2 + 2*a*b*x + b^2*x^2)^2),x]
[Out]
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Maple [A] time = 0.033, size = 319, normalized size = 1.6 \[ -{\frac{2\,{e}^{3}}{3\, \left ( ae-bd \right ) ^{4}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}+8\,{\frac{{e}^{3}b}{ \left ( ae-bd \right ) ^{5}\sqrt{ex+d}}}+{\frac{41\,{e}^{3}{b}^{4}}{8\, \left ( ae-bd \right ) ^{5} \left ( bex+ae \right ) ^{3}} \left ( ex+d \right ) ^{{\frac{5}{2}}}}+{\frac{35\,{e}^{4}{b}^{3}a}{3\, \left ( ae-bd \right ) ^{5} \left ( bex+ae \right ) ^{3}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}-{\frac{35\,{b}^{4}d{e}^{3}}{3\, \left ( ae-bd \right ) ^{5} \left ( bex+ae \right ) ^{3}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}+{\frac{55\,{e}^{5}{b}^{2}{a}^{2}}{8\, \left ( ae-bd \right ) ^{5} \left ( bex+ae \right ) ^{3}}\sqrt{ex+d}}-{\frac{55\,{e}^{4}{b}^{3}ad}{4\, \left ( ae-bd \right ) ^{5} \left ( bex+ae \right ) ^{3}}\sqrt{ex+d}}+{\frac{55\,{e}^{3}{b}^{4}{d}^{2}}{8\, \left ( ae-bd \right ) ^{5} \left ( bex+ae \right ) ^{3}}\sqrt{ex+d}}+{\frac{105\,{b}^{2}{e}^{3}}{8\, \left ( ae-bd \right ) ^{5}}\arctan \left ({b\sqrt{ex+d}{\frac{1}{\sqrt{b \left ( ae-bd \right ) }}}} \right ){\frac{1}{\sqrt{b \left ( ae-bd \right ) }}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/(e*x+d)^(5/2)/(b^2*x^2+2*a*b*x+a^2)^2,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b^2*x^2 + 2*a*b*x + a^2)^2*(e*x + d)^(5/2)),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.244149, size = 1, normalized size = 0. \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b^2*x^2 + 2*a*b*x + a^2)^2*(e*x + d)^(5/2)),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{\left (a + b x\right )^{4} \left (d + e x\right )^{\frac{5}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/(e*x+d)**(5/2)/(b**2*x**2+2*a*b*x+a**2)**2,x)
[Out]
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GIAC/XCAS [A] time = 0.222147, size = 576, normalized size = 2.88 \[ -\frac{105 \, b^{2} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right ) e^{3}}{8 \,{\left (b^{5} d^{5} - 5 \, a b^{4} d^{4} e + 10 \, a^{2} b^{3} d^{3} e^{2} - 10 \, a^{3} b^{2} d^{2} e^{3} + 5 \, a^{4} b d e^{4} - a^{5} e^{5}\right )} \sqrt{-b^{2} d + a b e}} - \frac{315 \,{\left (x e + d\right )}^{4} b^{4} e^{3} - 840 \,{\left (x e + d\right )}^{3} b^{4} d e^{3} + 693 \,{\left (x e + d\right )}^{2} b^{4} d^{2} e^{3} - 144 \,{\left (x e + d\right )} b^{4} d^{3} e^{3} - 16 \, b^{4} d^{4} e^{3} + 840 \,{\left (x e + d\right )}^{3} a b^{3} e^{4} - 1386 \,{\left (x e + d\right )}^{2} a b^{3} d e^{4} + 432 \,{\left (x e + d\right )} a b^{3} d^{2} e^{4} + 64 \, a b^{3} d^{3} e^{4} + 693 \,{\left (x e + d\right )}^{2} a^{2} b^{2} e^{5} - 432 \,{\left (x e + d\right )} a^{2} b^{2} d e^{5} - 96 \, a^{2} b^{2} d^{2} e^{5} + 144 \,{\left (x e + d\right )} a^{3} b e^{6} + 64 \, a^{3} b d e^{6} - 16 \, a^{4} e^{7}}{24 \,{\left (b^{5} d^{5} - 5 \, a b^{4} d^{4} e + 10 \, a^{2} b^{3} d^{3} e^{2} - 10 \, a^{3} b^{2} d^{2} e^{3} + 5 \, a^{4} b d e^{4} - a^{5} e^{5}\right )}{\left ({\left (x e + d\right )}^{\frac{3}{2}} b - \sqrt{x e + d} b d + \sqrt{x e + d} a e\right )}^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b^2*x^2 + 2*a*b*x + a^2)^2*(e*x + d)^(5/2)),x, algorithm="giac")
[Out]